
Differential Input Balanced Output Differential amplifier.

Design: The design of MOSFET Differential amplifier is as shown in below equations
Given Rd1=Rd2=25KΩ, VDD=5V, VSS=-5V, VTN1=VTN2=1V, kn1=kn2=50uA / Vsquare.
By DC Analysis
V_GSQ=VSS-2I_DQ* R_S           (1)
I_DQ=kn〖(V_GSQ-V_TN)〗^2       (2)
Substituting and Solving (1) and (2)
V_GSQ=2.186v=V_GSQ1=V_GSQ2
I_D=70.33uA
(g_m=2kn(V_GS-V_TN )=0.1186uA)⁄(v=g_m1=g_m2 )
Differential gain A_d=(g_m R_D )=2.965
The amplifier is designed for a gain of 2.965.


The team gave a very good support. Thanks to Kunal Sir for providing access to two courses on udemy.
The first course guided me on understanging MOSFET and basics of simulations.
The Second DAC IP course was more usefull  carry out the simulation.
Through this course I got to know how to install skywater and use it to model MOS.

I had choosen a simple circuit hence did not face issues in putting the circuit. but had errors in plotting the difference of output.
The VSD team supported me through Slack.com. The reply was very quick here.
I also learnt a little of paper writing. 
